1D LGCP bin count simulation and comparison with data
A common procedure of analyzing the distribution of 1D points is to chose a binning and plot the data's histogram with respect to this binning. This function compares the counts that the histogram calculates to simulations from a 1D log Gaussian Cox process conditioned on the number of data samples. For each bin this results in a median number of counts as well as a confidence interval. If the LGCP is a plausible model for the observed points then most of the histrogram counts (number of points within a bin) should be within the confidence intervals. Note that a proper comparison is a multiple testing problem which the function does not solve for you.
bincount( result, predictor, observations, breaks, nint = 20, probs = c(0.025, 0.5, 0.975), ... )
result |
|
predictor |
A formula describing the prediction of a 1D LGCP via |
observations |
A vector of observed values |
breaks |
A vector of bin boundaries |
nint |
Number of integration points per bin. Increase this if the bins are wide and |
probs |
numeric vector of probabilities with values in |
... |
arguments passed on to |
An data.frame
with a ggplot attribute ggp
## Not run: # Load a point pattern data(Poisson2_1D) # Take a look at the point (and frequency) data ggplot(pts2) + geom_histogram(aes(x = x), binwidth = 55 / 20, boundary = 0, fill = NA, color = "black") + geom_point(aes(x), y = 0, pch = "|", cex = 4) + coord_fixed(ratio = 1) # Fit an LGCP model x <- seq(0, 55, length = 50) mesh1D <- inla.mesh.1d(x, boundary = "free") mdl <- x ~ spde1D(map = x, model = inla.spde2.matern(mesh1D)) + Intercept # SOLUTION fit.spde <- lgcp(mdl, pts2, domain = list(x = c(0, 55))) # Calculate bin statistics bc <- bincount( result = fit.spde, observations = pts2, breaks = seq(0, max(pts2), length = 12), predictor = x ~ exp(spde1D + Intercept) ) # Plot them! attributes(bc)$ggp ## End(Not run)
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