Extract a character column into multiple columns using regular expression groups
Given a regular expression with capturing groups, extract() turns
each group into a new column. If the groups don't match, or the input
is NA, the output will be NA.
extract( data, col, into, regex = "([[:alnum:]]+)", remove = TRUE, convert = FALSE, ... )
data | 
 A data frame.  | 
col | 
 Column name or position. This is passed to
 This argument is passed by expression and supports quasiquotation (you can unquote column names or column positions).  | 
into | 
 Names of new variables to create as character vector.
Use   | 
regex | 
 a regular expression used to extract the desired values.
There should be one group (defined by   | 
remove | 
 If   | 
convert | 
 If  NB: this will cause string   | 
... | 
 Additional arguments passed on to methods.  | 
separate() to split up by a separator.
df <- data.frame(x = c(NA, "a-b", "a-d", "b-c", "d-e"))
df %>% extract(x, "A")
df %>% extract(x, c("A", "B"), "([[:alnum:]]+)-([[:alnum:]]+)")
# If no match, NA:
df %>% extract(x, c("A", "B"), "([a-d]+)-([a-d]+)")Please choose more modern alternatives, such as Google Chrome or Mozilla Firefox.